Jul 13, 2024 · WebThe probability density function (" p.d.f. ") of a continuous random variable X with support S is an integrable function f ( x) satisfying the following: f ( x) is positive everywhere in the support S, that is, f ( x) > 0, for all x in S. The area under the curve f ( x) in the support S is 1, that is: ∫ S f ( x) d x = 1.
find the value of c that makes the function continuous.
WebVIDEO ANSWER: consider the given piecewise function F of X, which is equal to erase the experts X rays to one over X. If X is not equal to zero and F of X equals see if X equals … Webfind c so that f is continuous at every point: f(x) = 2x^2+1 if x < pi; f(x) = c cos(x) -1, if x > or = to pi This problem has been solved! You'll get a detailed solution from a subject matter expert that helps you learn core concepts. sale on shore excursions royal caribbean
Find the value of c such that the function is continuous on - Quizlet
WebMar 16, 2024 · Transcript. Question 14 Find a and b , at if the function given by f(x) = { ( 2+ , <[email protected] +1, 1) is differentiable x = 1f(x) is differentiable at x = 1 if it is continuous. So, first we check if it is continuous. Check continuous f is continuous at x = 1 if L.H.L = R.H.L = (1) i.e. if lim (x 1^ ) ( ) = lim (x 1^+ ) ( ) = (1) lim (x 1^ ) ( ) = lim (x … WebOct 6, 2024 · There are many methods to solve this. I am going to use substitution. 4 = c + d Subtract c from both sides. 4 - c = d. d= 4 - c. 14 = 4c + d Substitute for d. 14 = 4c + 4 - c Combine like terms. 14 = 3c + 4 Subtract 4 from both sides. 10 = 3c Divide both sides by 3. WebJan 9, 2024 · c=-1, and, d=10. Let us name the Intervals x<1" as "I_1, 1lexlt2" as "I_2," and, "xge2" as "I_3. On these Intervals f is defined as polynomials, which, we know, are continuous on these intervals. So, if f has to be made continuous over the whole of RR, it has to be continuous at the joining points of these intervals; i.e., to say, it must be … things to see in vancouver british columbia