WebJun 13, 2024 · A for-loop is one of the main control-flow constructs of the R programming language. It is used to iterate over a collection of objects, such as a vector, a list, a matrix, or a dataframe, and apply the same set of … WebI'm trying to fill an empty matrix with results calculated from a for loop. I don't know how to specify the indexing in my for loop i.e., right now my for loop code does not work and I can't get result into my matrix. Here's a subset of my data:
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WebOct 12, 2024 · Here is a completely generic example on how to fill a matrix using for -loops in R: m = 100 n = 20 o = matrix (data = NA, nrow = m, ncol = n) for ( i in 1:m ) { for ( j in 1:n ) { o [i,j] = rnorm (n = 1) } } Or filling by row: m = 100 n = 20 o = matrix (data = NA, nrow = m, ncol = n) for ( i in 1:m ) { o [i,] = rnorm (n = n) } WebMar 25, 2024 · # Create a matrix mat <- matrix (data = seq (10, 20, by=1), nrow = 6, ncol =2) # Create the loop with r and c to iterate over the matrix for (r in 1:nrow (mat)) for (c in 1:ncol (mat)) print (paste ("Row", r, "and …
WebFeb 13, 2014 · I want each row of the matrix (w) to be repeatedly filled in matrix (mat) for time "d". matrix (run) is just so I can check that my loops are running correctly by recording the values run through matrix (w). here's my coding now: WebAug 9, 2011 · property<-function (mat) { #where mat is a matrix a=sum (mat) b=sum (colMeans (mat)) c=mean (mat) d=sum (rowMeans (mat)) e=nrow (mat)*ncol (mat) answer=list (a,b,c,d,e) return (answer) } x=matrix (c (1,0,1,0, 0,1,1,0, 0,0,0,1, 1,0,0,0, 1,0,0,1), byrow=T, nrow=5, ncol=4) obj=matrix (nrow=100,ncol=5,byrow=T) #create an …
WebApr 18, 2024 · The best idea is to save an empty matrix first and fill it in with the for loop nsim <- 100 #how many rbinom are w n <- 100000 size = 7 prob = 0.75 sim_data_vill_for_loop <- matrix (ncol = nsim, nrow = n) for (i in seq (nsim)) #iterate from 1 to nsim sim_data_vill_for_loop [, i] <- rbinom (n, size = size, prob = prob) #fill in 1 … WebJun 21, 2024 · First, start with your empty matrix: Nleaf <- matrix (nrow = 100, ncol = 1, 0) Now, define the function that you need to apply to the last hour's result to get the next hour's result ( obviously I've had to just make my own function up since you didn't share one in the question. This just multiplies the last hour by 0.9 and adds 0.11 ):
WebExample: First, select pm [1] for the first column. Second, select w [i] for each row in the first column. Store the formula in L_por_tmp and use it to fill the first column from row1 to row15. The whole procedure should start all over again for the second column (with pm [2]) with w [i] for each row and so on. wu and L are fixed in the formula.
WebMar 6, 2012 · Okay, the first thing you need to know is how to append things to a vector. Easily enough the function you want is append: x <- c (1, 2) x <- append (x, 3) will make the vector x contain (1, 2, 3) just as if you'd done x <- (1, 2, 3). The next thing you need to realise is that each member of your target vector is double the one before, this is ... scottish poems robert burnsWebJun 23, 2024 · # Create a matrix of 3X5 M1 = matrix (data = NA, ncol = 5, nrow = 3); row1<-c (1,2,3,4,5) row2<-c (6,7,8,9,10) M1 [1,1:5]<-row1 M1 [2,1:5]<-row2 M1 Output: [,1] [,2] [,3] [,4] [,5] [1,] 1 2 3 4 5 [2,] 6 7 8 9 10 [3,] NA NA NA NA NA Share Improve this answer Follow answered Jun 19, 2024 at 16:31 App Work 21.8k 5 25 38 Add a comment Your … preschool fire drill printablesWebJun 2, 2024 · To create a matrix in R you need to use the function called matrix(). The … scottish pokemon trainerWebJun 28, 2015 · I have a preallocated matrix in R and need to fill it with data from a dataframe generated from a file having following format: 1-1-7 1-3-2 2-2-6 1-4-8 .... where the first column contains a row index, the second a column index, and the 3rd contains the values. Is there a faster/better way then the following loop? scottish poems by robert burnsWebDec 21, 2013 · You can proceed as follows: #extract the correlation r from LD results tc<-LD.object$"r" #build a three columns matrix with all the pairwise combination of two markers pwm<-combn (row.names (tc),2) pwld<-matrix (NA,nrow=ncol (pwm),ncol=3) pwld [,1:2]<-pwm [1:2,] #Fill the matrix for (aaa in 1:nrow (pwld)) { pwld [aaa,3]<-tc [pwld [aaa,1],pwld ... scottish poetry library maccaigWebDec 18, 2024 · One issue you're having is asking R to compute dim (X), which seems, given your first code chunk, like it should be a vector and thus have a length () but not a dim (). So this solution uses your matrix Y to … preschool fingerplays about familyWebOct 31, 2024 · and this array: res.tot <- array(NA,dim=c(2,1,5)) I need to fill the array res.tot with a values, in this way: [[1]] [1] [1] 1 [2] 1 [[2]] [1] [1] 5 [2] 5 ... [[5]] [1] [1] 9 [2] 9 in the array res.tot each value of a is repeated 2 times, and each repeated a value occupay a different z dimension. I tried with for loop in this way: preschool fingerplays with motions